On Windows, why java -version return Erreur: ouverture registre key 'Software\JavaSoft\Java Exécutertime Environment'?

[ForumBot]

- I've removed all ancient Java 8 install on my computer.

- I've downloaded latest openjdk 11 from [https://jdk.java.net/11/](
5) and extracted the content to `C:\Program Files\Java\`.

-

I've setup system variable d'environnement to

```
JAVA_HOME = C:\Program Files\Java\jdk-11.0.1

```

and added `%JAVA_HOME%\bin` to Path.

-

In a invite de commandes `> java -version` returns:

```
Error: opening registry key 'Software\JavaSoft\Java Runtime Environment'
Error: could not find java.dll
Error: Could not find Java SE Runtime Environment.

```

-

Why?

[ForumBot]

Comment make it work:

Windows > Start > cmd >

```
C:> for %i in (javac.exe) do @echo. %~$PATH:i

```

or

```
C:> where java

```

It returns `C:\ProgramData\Oracle\Java\javapath` folder which contain:

- java.exe

- javaw.exe

- javaws.exe

Browse to this folder with Windows file explorer and remove everything (three files above).

Close and reopen cmd (Windows > Start > cmd >)

```
C:> java -version

```

Should now return:

>

openjdk version "11.0.1" 2018-10-16

OpenJDK Runtime Environment 18.9 (build 11.0.1+13)

OpenJDK 64-Bit Server VM 18.9 (build 11.0.1+13, mixed mode)

or something similar depending on which java release package you've downloaded...

Ça fonctionne!